A first look at the (4-2) Oakland Raiders Week 7 matchup, on the road against the (2-3) Jacksonville Jaguars.
The Oakland Raiders head back out on the road, where they are undefeated this season thanks to victories over the Saints, Titans and Ravens. They face a surging Jaguars team, that is the winner of two straight.
The Jaguars are fresh off a one point win in Chicago following their bye week, and beat the Colts in London the game before that. The Raiders just suffered a stinging loss to the Chiefs at home.
The Raiders have a lifetime record of 3-4 against the Jaguars. They have won the last two matchups, but have never won in Jacksonville. They last played in there back in 2010 — a 38-31 loss. They last played in 2013 at the Raiders home opener, which was a 19-9 victory for Oakland.
1st Place Raiders
The Raiders are sitting on top of the AFC west, tied with the Broncos. As with everything else this breakout season, this is another “first time since 2002” moment.
The success so far this season has helped remind everyone how long it has been since they were this competitive.
Back-to-back road games in Florida
This game against the Jaguars is the first of two straight road games in Florida, as the Raiders play Tampa Bay the following week.
Jack Del Rio will keep in team in Florida after the battle with Jacksonville, in an effort to eliminate any potential travel fatigue. Otherwise the Raiders would fly back to Oakland, just to head right back out to Tampa.